If E=mc^2: algebraically, Vmax should = c^2, yes? Therefore, at any point for real physical objects, if c=299,792,458 m/s; c^2 = 89,875,517,873,681,800 m/s = Vmax(local), yes? ["(local)" is to acct for variable time]
Assuming a device could be constructed to produce a relatively stable gravitational distortion disproportional to (and much greater than indicated by) its actual mass (thus artificially slowing time locally for it), could that object and its artificial gravitational distortion be accelerated to or beyond c^2 relative to the faster time outside the artificial gravitational distortion?
Understanding that realization of the gravitational effect would include some delay, it seems at least superficially plausible foreign-body gravitational influence would be negligible.
For years, people thought the displacement hull was the only form for waterborne vessels; that's no longer true. The analogy is to accelerating a mass significantly beyond our perception of c.
2006-06-25
21:34:19
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4 answers
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asked by
wireflight
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