Wire 1 has a potential difference of 50 V across it and carries a current of 2 A. Wire 2 has a potential?

Question

difference of 100 V across it and also carries a current of 2 A. Compare the resistences, rates of flow of charge (current), and rates of flow of energy (power) in the two wires.

Would you us the equation P=IV to solve? If not, what?

Answer 1

V=IR

Wire 1:
50 = 2 * R1 => R1 is 25 ohms
Current = 2 amps
power = V*I = 2*50 = 100 watts

Wire 2:
100= 2* R2 => R2 = 50 ohms
Current=2amps
power = V*I = 100*2 = 200 watts

are you looking for ratios when you say "compare" ?
if yes: ratio of resistances is 1:2
ratio of currents is 1:1
and ratio of power is 1:2

Answer 2

Wire 1 has a resistance of 25 ohm.
Wire 2 has aresistance of 50 ohm

Current is given.

We can use p = iv.

Answer 3

assuming to complete the circuit that wires one and two have their own neautral. In the 50 v line, the resistance on the line (e=i*r) is 25 ohms. with power at 100 watts. On the 100 v line, resistance is 50 ohms and power is 200 watts. ( p=i*e)

Answer 4

when you say across it, i assume you mean between 2 points along each wire's length.

Then V = I*R where R = resistance. you have V and I (current).

you state the rates of flow of charge (amps = Coulombs of charge per second) and is independent of voltage.

P = I*V is correct for the flow of power (rate of energy).

Answer 5

R1/R2 = V1/I1 x I2/V2 = 50/2 x 2/100 = 0.5

I1/I2 = 2/2 = 1

Yes IV will be used.