2006-06-26 02:10:26 · 6 answers · asked by maureen029 1 in Science & Mathematics ➔ Physics
u=40
a=5
t=6
s=ut+i/2at^2
s=40*6+1/2*5*36
s=240+90
s=330m
2006-06-26 02:20:08 · answer #1 · answered by ghulamalimurtaza 3 · 0⤊ 0⤋
Using Calculus:
Velocity is the first derivative of a function
Acceleration is the second dirivative
Deceleration = f2(x) = -5
The equation for the velocity is
f1(x)= 40-5x
Therefore
f(x) = 40x - 2.5x^2
when x = 6
f(x) = 150 = answer
2006-06-26 09:38:40 · answer #2 · answered by Ralphy Wiggum 2 · 0⤊ 0⤋
Use kinematic equation
x = x0 + v0 * t + (1/2) * a * t^2
x0 = initial position = 0
v0 = initial speed = 40
t = time = 6
a = acceleration = -5 because it's decelerating
Plug and chug.
2006-06-26 09:28:39 · answer #3 · answered by Anonymous · 0⤊ 0⤋
v=u+at(formula)
v=40+(-5)(6)
v=10m/s
(2 after an expression=square) s=distance
v2=u2+2as(formula)
(10)square=(40)square+2(-5)(s)
100=1600-10s
10s=1500
s=1500/10
s=150m
2006-06-26 09:28:43 · answer #4 · answered by Ahmed Jadalla Bushra Badawi 4 · 0⤊ 0⤋
Using second equation of motion:
d = 150m
note: acceleration is negative
2006-06-26 09:28:18 · answer #5 · answered by Mr.Scientist 3 · 0⤊ 0⤋
look it up that's probalbly home or school work so im not telling u:D
2006-06-26 09:13:51 · answer #6 · answered by cat 3 · 0⤊ 0⤋