A 120 -V electric motor draws 2.5 A. (a) How many coulombs of charge pass through it in 15 min?

Question

(b) How many joules of energy does it use in 15 min?

Answer 1

q = I t
q = 2.5 C/s x 900 s = 2250 C = 2.3 kC

P = 120 V x 2.5 A = 300 watt
E = P x t
E = 300 J/s x 900 s = 270 kJ

Answer 2

1 coulomb is the amount of electric charge carried by a current of 1 ampere flowing for 1 second.

1C=1A x S

15 minutes= 15*60=900 seconds.

900 seconds x 2.5 Amps= 2250 Coulombs.



joule=C x V

joule= 2250 Coulombs x 120 V

or 270000 joules

Answer 3

a) Coulombs of charge = 2.5 x 60 x 15

b) Energy = 120x2.5x60x15 J

Answer 4

easily the formulation is I = Q / t, the situation I is the present in amps, Q is the fee in coulombs and t it the time in seconds. a million amp is a million coulomb consistent with 2d. what quantity seconds will it take for 500 coulombs to pass a area on the fee of five amps (5 coulombs consistent with 2d)? you are going to be able to desire to therapy this.

Answer 5

1 amp = 1 Coulomb per second, you do the math.

1 Joule per second = 1 Watt, you do the math.