i know that when the light intensity of a light source falling on an LDR is high, the resistance in the LDR falls and when the light intensity is low, the resistance of the LDR is high.
and i know that when resistance is high, current flowing through the LDR is low and vice versa.
however, whats the relationship between the voltage and the current in an LDR? are they directly or inversely proportional?
if the current in an LDR rises, will the potential difference also rise or fall?
this is quite important as i need it for this sensor i'm making at school.
if u've got ur information from a website, could you also mention the website here or create a link?
thanks
2007-01-19
06:08:36
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3 answers
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asked by
amandac
3
in
Physics