Math problem help please?

Question

Two jets leave Denver at 9:00 AM., one flying east as a speed 50/km/h greater than the other, which is traveling west. At 11:00 AM the planes are 2500 km apart. Find their speeds

Hint: Rate x Time = Distance

Ok....i got awkward answers..but im hoping someone else will figure this out.

Answer 1

The have gone 2500 km in 2 hours. So they are flying apart at a rate of 1250 miles per hour.

The plane flying east has a speed of R.
The plane flying west has a speed of R + 50
Together they equal 1,250.

R + R + 50 = 1250
2R = 1200
R = 600

So one plane is going 600 kph, the other is going 650 kph.

Answer 2

Let x be the speed of the slower plan
then x+50 is the speed of the second plane

Write the problem in the form of an equation:

rate x time = distance

rate x 2 hr = 2500 km
rate = 1250 km/hr

rate = the rate of the first plane plus the rate of the second
1250 = x + (x+50), solve the equation

1250 = 2x + 50

1200 = 2x
x = 600

so slow plane travels at 600 km/h
fast plane travels at 600 + 50 = 650 km/h

Answer 3

I'm assuming the jets traveledfor two hours and that this is not a trick question involving time zones.

Let x = speed of jet flying East, then
x- 50 = speed of jet flying west
So 2x +2(x-50) = 2500
4x- 100 = 2500
4x = 2600
x = 650 km/hr = speed of jet flying East
x-50 = 600km/hr = speed of jet flying West

Answer 4

let's call X the speed of the slower. X+50 is the other.

X + X+50 is the distance they collectively cover in an hour, or 2X+50.

After two hours [2 times (2X+50)], they've gone 2500 km.

4X+100=2500
subtract 100 from each side
4X=2400
divide by 4
X=600

double check:
600+650 each hour = 1250
2 hours = 2500

Answer 5

If x is the speed of the westward plane, then x + 50 is the speed of the eastward one.

In 2 hours, the westward one will travel 2 hours × x km/hr = 2x km

The eastward one will go 2 hours × (x + 50) km/hr = 2(x + 50) km

The sum of their distances is 2500 km.

2x + 2(x + 50) = 2500

4x + 100 = 2500

4x = 2400

x = 600

The eastward one is going 600 km/hr, and the westward one is going 650 km/hr.

Double check:

600 km/hr × 2 hours + 650 km/hr × 2 hours = 1200 km + 1300 km = 2500 km

Answer 6

Let x be the speed of the westward jet. Then the eastward jet is going at x+50.

They are growing apart at a rate equal to the sum of their speeds, i.e. rate = 2x+50. So you have the quation

Rate x Time = Distance
→ (2x+50) * 2 = 2500.

Solve for x.

Answer 7

the relative speeds will add up
so let the speeds be x and x+50 kph
distance=time*relative speed
=2(x+x+50)
=4x+100
equating
4x+100=2500
4x=2400
x=600
so he speeds are 600 and 650 km/hr respectively