IF G is a cyclic group, there exist exactly one intermediate field I of degree k, for each integer k dividing [K : F].
Well, anyway I have to prove that. here is my problem. Our textbook hasn't expalined in any way what a Cyclic Galois Group is at all.
I do know that a Cyclic Group consists of all the powers of the generator, and that every subgroup of cyclic group is cyclic, but it's really not helping me apply this to Galois groups.
Anyway if you know of this in any way or can point me in the right direction or what theorms to look at go for it. My brain is fried and I give up for now.
2006-11-26
08:45:35
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3 answers
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asked by
travis R
4
in
Mathematics