English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

V = 120sin(120(pi)t) If a resistance of R = 20 ohms is present, what is the current I (using Ohm’s Law V = IR)? What is the amplitude and period of the current I?

2006-11-26 08:42:54 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

The maximum value of sin(x) is 1.
V = 120(1) = 120.
120 = I*20
I=6 at Max

The sin function has a period of 360 deg.
2pi = 306 deg.
120(pi)t = 60 cycles of the function.

Is any of this right?

2006-11-26 09:23:50 · answer #1 · answered by STEVEN F 7 · 0 0

fedest.com, questions and answers