Try this problem below...?

Question

A rifle with a muzzle velocity of 2000 ft./sec. is fired horizontally at a height of five feet above level ground. Ignoring air resistance, how far (nearest whole foot) does the bullet travel from the end of the muzzle of the rifle before it strikes the ground

Answer 1

approximately 1107 feet i think
of course this is neglecting air resistance and mass of the bullet along with loss of energy heating

my work:
find the time that bullet is in air:
we know that height is 5 feet and the initial velocity of the downward component is 0 because the gun was fired horizontally.
using second kinematics equation :
intial velocity(time) + 1/2(acceleration)(time)^2 = distance
we fill in:
0(t)+1/2(32.67ft/sec^2)(t^2) = 5 and solve for t which = .553283
Now that we know the time bullet spends in the air we can find the distance by using time and the same equation but using all horizontal component.
we will in:
2000(.553283)+1/2(0*)9.5532830^2 which equals =1106.57 or about 1107

* = there is no acceleration since there is no gravitaional effect on horizontal component

i made have made a mistake so please check

Answer 2

Not soluble. Also need to know the mass of the bullet.

Answer 3

You need the mass of the projectile. It is a matter of momentum.

Answer 4

how heavy is the bullet ???

Answer 5

i got 1100ft

Answer 6

no answer