A car traveling at a speed of vo = 58 m/s stops smoothly (that is, its deceleration is constant) over a distance of d = 111 m. a) What is its acceleration during the time it is stopping? (Be careful about the sign!)
a = m/s2
-5.07 NO
b) How long (what amount of time) does it take for the car to come to a stop?
tstop = s
c) After the car has gone 1/3 of the stopping distance, what is its speed?
v1/3 = m/s
27.76 NO
HELP: Dx = d/3
d) If the car had been going 10 m/s but had stopped in the same d = 111 m distance, what would its acceleration have been?
a(vo = 10m/s) = m/s2
2006-08-29
19:28:28
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1 answers
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por_ti_a_17
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