Length of simple pendulum = 0.760 m
Pendulum bob = 0.365 kg
Theta = 12.0 degrees
a) Find the frequency (Don't bother with this part)
b) What is the pendulum bob's speed when it passes thru the lowest point of the swing? (equilibrium)
c) What is the total energy stored in this oscillation, assuming no loss? (use answer from #2)
**assume simple harmonic motion for all questions
-For part 2, I've tried 3 different approaches, and I don't know which is correct:
1) centripetal force
mv^2/r = Tension- mg...but how to find tension?
2) definition of v:
v = x/t
x = 2* L * theta
1/t = frequency
v = 2*l*theta*frequency (this is what I think works)
3) Find total energy first; Total energy = (1/2)kA^2
k = mg/L for a simple pendulum
A = L * theta
So, the total energy is: (1/2)(mg/L)(L*theta)^2
Then, this amount equals (1/2)mv^2
so solve for v:
root((g)(theta)^2*L) = v
So, my best tries are:
v = root(gL*theta^2)
v = 2L*theta *frequency
which is correct?
2007-05-26
15:54:29
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2 answers
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asked by
J Z
4