...varies with time t according to Flux = 3at^3 - bt^2, with a = 1.5s^-3 m^2T, and b = 6.1 s^-2m^2T. The resistance of the ring is 2.7 ohms. Determine the maximum current induced in the ring during the interval from t1 = -3.6 s to t2 = 1.6 s.
I began this problem by doing the derivative of the equation given for flux. The new derived equation I obtained was t(13.5t - 12.2). I know that Emf = dFlux/dt. I just don't know what the t in my derived flux equation represents, t1 or t2, or if I have to use both and subtract. In any case, I know to find current you just divide the induced emf by the resistance. Any help would be appreciated.
2007-04-10
06:07:49
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2 answers
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asked by
mmrage318
1