Uniform Eletric Flux...?

Question

A circular region of radius R = 3.00 cm in which a uniform electric flux is directed out (imagine it on your screen, it's pointing OUT). The total electric flux enclosed by the region is given by Phi ^ elec = (3.00 mV m/s)t, where t is time.

What is the magnitude of the magnetic field that is induced at radial distances (a) 2.00 cm and (b) 5.00 cm?

Explain your work, and good luck! :)

Answer 1

EDIT: A more detailed description is here
http://img441.imageshack.us/img441/9059/uniformelectricfieldfd5.png

Solve this with the equation

∫H*dl = -∫∂D/∂t*dA the left is a line integral and the right is a surface integral.

Since the field is uniform, the line integral is just the field times the length, and in this case the length is the circumference of the circle at the radial distances given.
2*π*r*H

The surface integral represents the total flux enclosed, or for a uniform field, flux density times area. Find the density from the total flux at 3.00cm, then find totat flux enclosed at 2.00cm and 5.00cm

Note that D = e0*E, where e0 = permittivity of space.

The partial ∂D/∂t, will be the coefficient of t.

Solve for H. The magnetic field is then B = µ0*H, µ is permeability of space.

Answer 2

electric powered flux is the style of electric powered lines of rigidity passing usually by a floor. Mathematically it fairly is comparable to the dot made of electric powered container and the section vector linked with the outdoors. electric powered container intensity at a factor is comparable to the electrical powered flux according to unit section for an infinitesimally small section drawn perpendicular to the electrical powered container approximately that factor.