A rotating fan completes 1200 revolutions every minute. Consider the tip of a blade, at a radius of 0.15 m. a)

Question

A rotating fan completes 1200 revolutions every minute. Consider the tip of a blade, at a radius of 0.15 m. a)through what distance does the tip move in one revolution? What are b) the tip's speed and c) the magnitude of its acceleration? d) What is the period of the motion?

Answer 1

a) 2pir=2 x 3.14159.. x .15=0.94m
b) v=2 pi r (rpm)/60=18.85 m/sec
c) centripetal acceleration=(v^2)/r where v=2 pi r rpm/60
a=(18.85)^2/.15=2369 m/sec^2
d) 1/(rpm/60) T=60/1200=0.05 sec

Answer 2

a) circumference = 2 pi r

b) speed = circumference / period
= circumference * frequency

c) centripetal acceleration = v^2 / r

d) The period is just one over the frequency