A ball is thrown at an angle of 53 degrees above the horizontal off the roof of a building with an initial speed of 15 m/s. Find the position and velocity of the ball at 1.0s, 2.0s and 4.0s after it was thrown (ignore air resistance) (x- components are horizontal y components are vertical)
What is the x, y, Vx, Vy and V for the ball at 1.0s, 2.0s and 4.0s
I used equation V=at+Vo to solve for V and X-Xo=.5(V+Vo)t to solve for x.
I got 9m/s for Vox, 12m/s for Voy, ax = -9.8m/s^2 and ax= 0m/s^2
Time = 1.0s, x = 9m, y = 7.1m, Vx= 9m/s, Vy =2.2m/s and V = 15 m/s
Time = 2.0s, x = 18m, y = 4.4m, Vx= 9m/s, Vy =-7.6m/s and V = 15 m/s
Time = 4.0s, x = 9m, y = -15.2m, Vx= 9m/s, Vy =-27.2m/s and V = 15 m/s
thanks
2007-03-02
01:30:14
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3 answers
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asked by
Anonymous