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Your question is not very clear to me. Let's discuss what a black hole is and how light is trapped inside a black hole:
Black Hole:
A black hole is a super dense object that has an intense gravitational pull. There are two parts to a black hole, a singularity and a event horizon.

The event horizon is where the force of gravity becomes so strong that even light is pulled into the black hole. Although the event horizon is part of a black hole, it is not a tangible object. If you were to fall into a black hole, it would be impossible for you to know when you hit the event horizon.

The singularity is not really a tangible object either. According to the General Theory of Relativity the Singularity is a point of infinite space time curvature. This means that the force of gravity has become infinitely strong at the center of a black hole. Everything that falls into a black hole by passing the event horizon, including light, will eventually reach the singularity of a black hole. Before something reaches the singularity it is torn apart by intense gravitational forces. Even the atoms themselves are torn apart by the gravitational forces.


Light from a Black Hole:
One of their basic properties of black holes is that they trap light. According to the special theory of relativity (and also according to the general theory since it contains the special theory) that nothing exceeds the speed of light.

The particles of light, called the photons lose energy when travelling out of a gravitational field and appear to be redder to an external observer. . The stronger the gravitational field, the more energy the photons lose because of this gravitational redshift. The extreme case is a black hole where photons from within a certain radius lose all their energy and become invisible.

Another view of the same phenomenon is that the light can not escape out of a black hole as it can not go pass the event horizon. The event horizon is the point outside the black hole where the gravitational attraction becomes so strong that the escape velocity (the velocity at which an object would have to go to escape the gravitational field) equals the speed of light. Since according to the relativity theory no object can exceed the speed of light that means nothing, not even light, could escape the black hole once it is inside this distance from the center of the black hole.

A more fundamental way of viewing this (the same phenomenon) is that in a black hole, the gravitational field is so intense that it bends space and time around itself so that inside the event horizon there are literally no paths in space and time that lead to the outside of the black hole: No matter what direction you went, you would find that your path led back to the center of the black hole, where the singularity is found.

Black Hole Radiation:
Recent attempts to understand black holes on a quantum level have indicated that they radiate thermally (they have a finite temperature, though one incredibly low if the black hole is of reasonable size) that is proportional to the gradient of the gravity field. This is due to the capture of virtual particles decaying from the vacuum at the horizon. These are created in pairs and one of them is caught in the black hole and the other is radiated externally. This has been interpreted by Hawking as a tunneling effect and as a form of Unruh radiation. This may give some clever and knowledgeable researcher enough information to figure out what's happening at the center someday.

2007-03-01 21:14:41 · answer #1 · answered by Dalilur R 3 · 0 0

Speed of light in a vacuum is approximately: 2.99792458 x 10^8m/sec.
http://scienceworld.wolfram.com/physics/SpeedofLight.html
Also check out: http://en.wikipedia.org/wiki/Speed_of_light for a good history and explanation of what is known about light.
Speed of sound through air at sea level and 21 degrees C, is 344 m/s. Of course the speed of sound varies with the medium and with temperature, and does not travel through a vacuum.
http://en.wikipedia.org/wiki/Speed_of_sound
As for light traveling through a black hole, wouldn't you need to measure both its entry and exit speed to determine any variation?

2007-03-01 17:46:22 · answer #2 · answered by lynn y 3 · 0 0

you will not could manage the fee of light to be certain the colors surrounding a non-feeding, non-rotating black hollow yet basically prefer a telescope effective adequate and anticipate that Hawking Radiation is real, or be close adequate to view it including your very own eyes. i think of you will see a black circle surrounded via a rainbow of colorings with violet next to the form horizon accompanied via the different colorings of the spectrum with pink the furthest out. The rainbow result and that's my terrific guess. If the black hollow is rotating then physique dragging will make an odd looking rainbow.

2016-12-14 08:40:35 · answer #3 · answered by ? 4 · 0 0

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