Physics - October 2006

I am having problems understanding what happens to electrons once they have exited a reisitor. For example, lets say you a very simple circuit - a 12V battery with a single bulb attached using a couple of wires. Now let's imagine the 'go' and 'return' wires have 0 resistance. If you was to now place a multimeta on the terminals each side of the bulb, it would read 12V - incidating that ALL the volage has dropped across the bulb. This is what I don't understand - if voltage is the moving 'force' and all the 'force' is used-up pushing the electrons through the bulb, then what is giving the electrons the 'force' or 'power' to return down the wire and back into the battery if all their kinetic engery has been used getting through the bulb?

2006-10-22 13:12:17 · 7 answers · asked by mike_n_1976 1

Colors are produced by changing the intensity of the red-R, green-G, and blue-B pixels. What color would the following represent? (The number in the parenthesis measures the intensity of the color)
1. R(100), G(0), B(0)
2. R(100), G(100), B(100)
3. R(0), G(0), B(0)
4. R(100), G(0), B(100)

2006-10-22 13:11:44 · 3 answers · asked by Meder 2

2006-10-22 13:09:07 · 2 answers · asked by Meder 2

could a little play race car be considered as a wheel and axel? and a mechanical device a simple machine?

2006-10-22 12:48:52 · 1 answers · asked by Anonymous

forward and opposite to the direction of force of friction?

2006-10-22 12:47:27 · 3 answers · asked by 8 3

2006-10-22 12:41:15 · 5 answers · asked by bebackhome_safe 2

2006-10-22 12:40:16 · 4 answers · asked by Rachel N 1

like gravity

2006-10-22 12:31:30 · 5 answers · asked by 8 3

A 0.50 kg object is at rest at the origin of a coordinate system. A 2.4 N force in the +x direction acts on the object for 1.2 s.
(a) What is the velocity at the end of this interval?
m/s
(b) At the end of this interval, a constant force of 4.7 N is applied in the -x direction for 3.4 s. What is the velocity at the end of the 3.4 s?
m/s

2006-10-22 12:24:32 · 2 answers · asked by activegirl 1

A force of 15N acts on a 5kg mass, another force of 6N acts in the opposite direction. If mass is initially at rest, find the time rate of change of momentum.

I'm unsure what formula to use. Of course, the prof gives homework questions COMPLETELY different from what we did in class and has us all confused!

THANKS FOR THE HELP!!

2006-10-22 12:08:29 · 2 answers · asked by alonso_fan85 1

The question asks:
Find the acceleration of a car whose initial speed is 30 m/s and slows uniformly to 10 m/s in 5 seconds. Then, determine the distance it travels in the 3rd second (t=2 to t=3).
Is this right?
a) Acceleration:
10m/s -30m/s / 0s - 5s = -20m/s / -5m/s = 4m/s^2

b)Distance:
X3= 30m/s(3s) + 1/2(4m/s^2)(3s)^2 = 90m+18m= 108m
X2= 30m/s(2s) + 1/2(4m/s^2)(2s)^2 = 60m+ 8m = 68m
X =108-68=40m

2006-10-22 12:07:37 · 2 answers · asked by crazed1511 1

a 12600kg railroad car travels on a level frictionless track with constant speed of 18m/s. a 5350 kg load, initially at rest, is dropped onto the car. what will be the car's new speed?

How do I do this problem. where do i start??

2006-10-22 12:02:22 · 2 answers · asked by Anonymous

acceleration is...

1. south east
2. north east
3. east
4. south
2. no acceleration

2006-10-22 11:59:08 · 1 answers · asked by 8 3

time of flight...

1. increases and horizontal range decreases
2. decreases and horizontal range decreases
3. increases and horizontal range increases
4. decreases and horizontal range increases
5. stays constant but horizantal range decreases

2006-10-22 11:41:59 · 4 answers · asked by Anonymous

destination? (is it north west)

Another question,
if a plane wants to fly south-west and a wind makes it go west, is the wind coming from the north-west?

2006-10-22 11:37:42 · 4 answers · asked by Anonymous

A car of mass 1.2 103 kg is traveling east at a speed of 30 m/s along a horizontal roadway. When its brakes are applied, the car stops in 5.8 s. What is the average horizontal force exerted on the car while it is braking?

2006-10-22 11:32:54 · 2 answers · asked by activegirl 1

what is the difference between mass and weight? are they measured in different units?

2006-10-22 11:29:56 · 12 answers · asked by superman 3

2006-10-22 11:27:33 · 9 answers · asked by STORMY K 3

Imagine a railway carriage full of water is moving at constant velocity along an infinitely long,
straight, level, frictionless track when it develops a leak and water begins to flow out at a constant
rate, straight downwards. Discuss what will happen to the velocity of carriage as the mass of the
carriage changes. Your answer should refer to Newton’s Laws of Motion as appropriate, and to
the Principles of Conservation of Momentum and Conservation of Energy.

2006-10-22 11:26:43 · 6 answers · asked by alan_warr 2

arms. As collide, while holding each other, with what speed do you both move off together?

a.) 2.2 m/s
b.) 5.0 m/s
c.) 23 m/s
d.) zero

2006-10-22 11:04:24 · 3 answers · asked by Kenya W 1

Earth?
1. 16 times
2. 8
3. 4
4. 2
5. the same

2006-10-22 10:57:42 · 2 answers · asked by Anonymous

2006-10-22 10:52:23 · 4 answers · asked by slayer_17 1

2006-10-22 10:42:35 · 4 answers · asked by Anonymous

2006-10-22 10:26:56 · 13 answers · asked by bonehead 1

How come the displacement vector for an object moving in 2D be longer than the length of path traveled by the object over the same time interval but not less than?

2006-10-22 10:17:31 · 2 answers · asked by sleepy 1

2006-10-22 10:17:20 · 3 answers · asked by goring 6

Why cant you get a sun burn behind glass this has always confused me

2006-10-22 10:10:47 · 8 answers · asked by hayzman22 1

Why can light travel in a vacum?

2006-10-22 09:48:05 · 3 answers · asked by hayzman22 1

2006-10-22 09:34:00 · 3 answers · asked by lisa 1

A 10kg box rests ona ramp that is laying flat. The coefficient of static friction ( µs ) is 0.50, and the coefficient of kinetic friction ( µk) is 0.30.....

what is the force (Fp) necessary to keep the box sliding at a CONSTANT VELOCITY?

I'm not really sure how to work this problem...this is the only thing i could come up with, but I dont think its right...could check this plz?

∑Fy = Fn - Fg = 0 , therefore
Fn = Fg = mg = 10kg*9.8m/s2 = 98N

∑Fx = Fp - Ffk = 0, therefore
Fp = Ffk = µk(Fn) = 0.30 (98N) = 29.4N


The reason why I think there might be something wrong with this is b/c i calculated the max static friction (Ffs) to be 49N...Im really confused could someone plz help me?

2006-10-22 09:08:52 · 1 answers · asked by Sir Excalibur 2