like gravity
2006-10-22 12:31:30 · 5 answers · asked by 8 3 in Science & Mathematics ➔ Physics
No its not 9.8
its 9.8 m/s^2 * sin(angle)
and the angle is same inclination angle.
2006-10-22 14:57:43 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Of course the acceleration on the system is the acceleration of gravity (9.8 m/s/s at the Earth's surface), but the component of the acceleration parallel to the ramp is
(9.8 m/s/s) * sin(angle)
where (angle) is the angle of the ramp from the horizontal.
2006-10-22 19:36:03 · answer #2 · answered by cosmo 7 · 0⤊ 0⤋
No. It's only 9.8 on earth in free fall. You have to know a bit of trigonometry to figure that one. Since you didn't give the angle I can't tell you the answer.
2006-10-22 19:39:17 · answer #3 · answered by Anonymous · 0⤊ 0⤋
No. The force pulliing the box is m*g*sin(T), therefore the acceleration is g*sin(T). Only when T is 90º (verticla) is the accleration = g. When T = 0º (ramp is horizontal) the acclereration is zero.
2006-10-22 19:38:55 · answer #4 · answered by gp4rts 7 · 1⤊ 0⤋
no its centrifugal deliniation causes gravitational diminuation ...and the stuff would fall out of the box and perhaps get damaged
2006-10-22 19:36:29 · answer #5 · answered by fuufingf 5 · 0⤊ 0⤋