What is the velocity at the end of the interval?

Question

A 0.50 kg object is at rest at the origin of a coordinate system. A 2.4 N force in the +x direction acts on the object for 1.2 s.
(a) What is the velocity at the end of this interval?
m/s
(b) At the end of this interval, a constant force of 4.7 N is applied in the -x direction for 3.4 s. What is the velocity at the end of the 3.4 s?
m/s

Answer 1

5.76 m/s

f=ma
u find out that acceleration is 4.8 m/s2

v2=v1+at
v2=0+(4.8)(1.2)
=5.76 m/s

use this info to answer part B

Answer 2

F=m*a, so accel a = F/m Velocity is a*t. The same formula applies tpop part b) except the accel is negative and the velocity is v0 - a*t