The question asks:
Find the acceleration of a car whose initial speed is 30 m/s and slows uniformly to 10 m/s in 5 seconds. Then, determine the distance it travels in the 3rd second (t=2 to t=3).
Is this right?
a) Acceleration:
10m/s -30m/s / 0s - 5s = -20m/s / -5m/s = 4m/s^2
b)Distance:
X3= 30m/s(3s) + 1/2(4m/s^2)(3s)^2 = 90m+18m= 108m
X2= 30m/s(2s) + 1/2(4m/s^2)(2s)^2 = 60m+ 8m = 68m
X =108-68=40m
2006-10-22
12:07:37
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2 answers
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asked by
crazed1511
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in
Science & Mathematics
➔ Physics