hii ok so i have another homework question..
- use the graphs to determine the equation of the qudratic functions in standard form.
its a parabola opening down, the roots are at -4 and 7. and they give me another point which is (6,32). there is no vertex point given.
i started by doing this :
a(x+4)(x-7) =0
a(x^2-7x+4x-28)=0
a(x^2-3x-28)=0
then i plugged in the points to find a.
32=0(36-18-28)
32=(a)(-10)
NOW, here's where the problem is..
a is supposed to equal -3.2. (the answer is -3.2x^2+9.6+89.6).
but how is 32*10 = -3.2??? :S :S
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also, how do you find the equation when its a parabola opening up. they only give you the vertex (3,5) and one point on the graph which is (9,-35) ??
please include the steps in your answer plz!! :) thx!
2007-07-07
09:13:19
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3 answers
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asked by
mystery_girl07
2