What is the antiderivative of (1 - x)^9?

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2007-07-07 09:41:54 · 5 answers · asked by ballin2thefullest 1 in Science & Mathematics ➔ Mathematics

General formula- Integral of X^n = [X^(n+1)]/(n+1)

Anti-derivative = - [(1 - x)^10]/10

2007-07-07 09:45:53 · answer #1 · answered by Anonymous · 0⤊ 0⤋

Integration my son is key

\int (1-x)^9

-(1-x)^10 / 10

2007-07-07 09:45:15 · answer #2 · answered by Anonymous · 0⤊ 0⤋

I = ∫ (1 - x)^9 dx
let u = 1 - x
du /dx = - 1
du = - dx
- du = dx
I = - ∫ u^9 du
I = - u^10 / 10 + C
I = - (1 - x)^10 / 10 + C

2007-07-11 07:52:15 · answer #3 · answered by Como 7 · 0⤊ 0⤋

-0.1(1-x)^10 + constant of integration

2007-07-07 12:43:59 · answer #4 · answered by dr_no4458 4 · 0⤊ 0⤋

(-1/10)(1-x)^10

To see it, you can let u = 1-x.

2007-07-07 09:45:57 · answer #5 · answered by TFV 5 · 0⤊ 0⤋