4a^2 - 4a + 1 ? how can i factor this?

Question

explanation would be useful..thanks

Answer 1

4a^2 -4a +1
(2a - 1) X (2a -1)
(2a X 2a) + (-2a -2a) + (-1 X -1)

Answer 2

start up by using factoring all expressions: [(2a² + a - 6) / (a² + 4a - 5)] × [(a³ - 3a² + 2a) / (4a² - 6a) [(2a - 3)(a + 2) / (a + 5)(a - a million)] × [a(a² - 3a + 2) / 2a(2a - 3)] [(2a - 3)(a + 2) / (a + 5)(a - a million)] × [a(a - 2)(a - a million) / 2a(2a - 3)] [a(2a - 3)(a + 2)(a - 2)(a - a million)] / [2a(a + 5)(a - a million)(2a - 3)] [(a + 2)(a - 2)] / [2(a + 5)] [(x2 - x - 6) / (y2 + 3y - 10)] · [(y2 - 7y 10) / (3x2 x - 10)] ÷ [(x2 - 2x - 3) / (9x2 - 25)] = [(x - 3)(x + 2) / (y - 2)(y + 5)] × [(y - 2)(y - 5) / (3x - 5)(x + 2)] / [(x + a million)(x - 3) / (3x - 5)(3x + 5)] = [(x - 3)(x + 2) / (y - 2)(y + 5)] × [(y - 2)(y - 5) / (3x - 5)(x + 2)] × [(3x - 5)(3x + 5) / (x + a million)(x - 3)] = (x - 3)(x + 2)(y - 2)(y - 5)(3x - 5)(3x + 5) / (y - 2)(y + 5)(3x - 5)(x + 2)(x + a million)(x - 3) = (y - 5)(3x + 5) / (y + 5)(x + a million)

Answer 3

answer is =(2a-1)^2
explanation if the middle term is the twice of the root of the first term times of the root of the third term as the following 2x(4a^2)^0.5x(1^0.5)=(+ or -) (4a) equal the middle term (-4a) then it can be resolved to quadratic form the first term equal the root of first and the second equal the root of the last term (constant term )but has the same sign of the of the middle term

Answer 4

Factors are (2a-1)(2a-1), i.e. (2a-1)^2. See my answer to your other question on the subject for an explanation.

Answer 5

First require factors of 4a².
Try 2a and 2a:-
(2a*****).(2a******)
Now require factors of 1 that combine with 2a and 2a to give - 4a.
Try -1 and -1:-

(2a - 1).(2a - 1)
Check
2a.(2a - 1) - 1.(2a - 1)
= 4a² - 2a - 2a + 1
= 4a² - 4a + 1 as required.

Answer 6

(2a^2 - 1)(2a^2 - 1)...this does not really need any explanation..just multiply out.

Answer 7

4a^2 -4a +1

(2a - 1) X (2a -1)

(2a X 2a) + (-2a -2a) + (-1 X -1)

Answer 8

if trial and error doesn't work use the Formula

x = - b +/- sqrt b^2 - 4ac / 2a

Answer 9

(2x-1)^2