Find x: log(base2)(3x+2)=5
2007-07-07 08:20:58 · 7 answers · asked by jordan 2 in Science & Mathematics ➔ Mathematics
42. XD
oh wait no. that's the meaning of life. hehe.
2007-07-07 08:23:46 · answer #1 · answered by Believe in Unicorns 2 · 0⤊ 1⤋
1
2007-07-07 15:22:58 · answer #2 · answered by Anonymous · 0⤊ 1⤋
log(base2)(3x+2)=5 convert it into exponential form
2 to the power of 5 = 3x+2
therefore
32=3x+2
30=3x
x=10
2007-07-07 15:24:19 · answer #3 · answered by dogtownbootleggers 2 · 0⤊ 0⤋
Let log be log to base 2
log (3x + 2) = 5
3x + 2 = 2^5
3x + 2 = 32
3x = 30
x = 10
2007-07-07 15:38:38 · answer #4 · answered by Como 7 · 0⤊ 0⤋
log_b a = x ==> b^x = a (note: b is the base)
log_2 (3x + 2) = 5
2^5 = 3x + 2
32 = 3x + 2
30 = 3x
x = 10
2007-07-07 15:24:24 · answer #5 · answered by 7 · 0⤊ 0⤋
2^5=3x+2
32-2=3x
x=30/3=10
2007-07-07 15:27:52 · answer #6 · answered by iyiogrenci 6 · 0⤊ 0⤋
x = b^y is the same as y = log (base b)x
So
2^5 = 3x + 2
32 = 3x + 2
x = 10
2007-07-07 15:24:27 · answer #7 · answered by misscarinne 4 · 0⤊ 0⤋