2007-07-07 07:03:51 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The problem factors as: (x-3)(x-2) = 0
2007-07-07 07:06:37 · answer #1 · answered by Anonymous · 1⤊ 0⤋
If you factor this, you get (x-3)(x-2) = 0 as -3*-2 = 6 and -3+-2 = -5. Then you can see that if two factors have a product equal to 0, then 1 has to be 0. So, x-3=0 or x-2 = 0. So, x = 3 or x =2
2007-07-07 14:07:01 · answer #2 · answered by magixter 2 · 0⤊ 0⤋
x²-5x+6=0
(x-3)(x-2)=0
x-3=0 or x-2=0
x=3 or x=2
2007-07-07 14:08:20 · answer #3 · answered by gm 2 · 0⤊ 0⤋
x^2-5x+6=(x-2)(x-3)=0
Two cases: x-2 is zero or x-3 is zero.
And x-2 = 0 when x = 2, x-3=0 when x=3.
2007-07-07 14:07:46 · answer #4 · answered by olens 2 · 0⤊ 0⤋
(x-2)(x-3)=0
so
x-2=0 or x-3=0
x=2 or x=3
2007-07-07 14:06:49 · answer #5 · answered by MeisəM 4 · 0⤊ 1⤋
(x-3)(x-2)
2007-07-11 06:24:22 · answer #6 · answered by ♫●GARV●♫ 6 · 0⤊ 0⤋
(x - 3).(x - 2) = 0
x = 3 , x = 2
2007-07-08 11:40:38 · answer #7 · answered by agratefuldog 3 · 0⤊ 0⤋
(x - 3).(x - 2) = 0
x = 3 , x = 2
2007-07-07 15:56:51 · answer #8 · answered by Como 7 · 0⤊ 0⤋