72 - 22x + x^2 how can i factor this?

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72 - 22x + x^2 how can i factor this?

2007-07-07 07:14:39 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

5 answers

(x - 18).(x - 4)

2007-07-10 23:20:48 · answer #1 · answered by Anonymous · 1⤊ 0⤋

x^2-22x+72=0
(x-4)(x-18)=0
x=4 & x=18

2007-07-07 07:29:29 · answer #2 · answered by f1rstbornson 2 · 0⤊ 0⤋

xÂ² - 22x + 72 = (x - 18).(x - 4)

2007-07-07 08:36:28 · answer #3 · answered by Como 7 · 0⤊ 0⤋

(x-18)(x-4)
If you get stuck, just check sqrt(b^2-4ac) which in this case is 14. So roots are (22+14)/2 = 18 and (22-14)/2 = 4.
So factors have to be (x-18) and (x-4).

2007-07-07 07:30:15 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋

(x-18)(x-4) or (18-x)(4-x)

2007-07-07 07:19:47 · answer #5 · answered by blahman 2 · 0⤊ 0⤋