2007-07-07 07:02:41 · 4 answers · asked by Ryan A 1 in Science & Mathematics ➔ Mathematics
5.(x + 3).(x - 2)
2007-07-10 23:25:01 · answer #1 · answered by Anonymous · 1⤊ 0⤋
5x^2+5x-30
factor out a 5 to make factoring easier for you.
5 [ x^2 + x - 6 ]
What 2 factors of (-6) can give you a difference that equals 1? (1 is the coefficient of the middle term {x} )
(I like -2 and 3.)
5x^2+5x-30 = 5(x-2)(x+3)
You can check by working backwards.
Multiply (x-2)(x+3) then multiply this answer by 5.
(x-2)
(x+3)
-------------
x^2 - 2x + 3x - 6
= [ x^2 + x - 6 ] when you combine like terms.
5*[ x^2 + x - 6 ] = 5x^2 + 5x - 30
2007-07-07 14:10:34 · answer #2 · answered by The Grey Pilgrim 1 · 0⤊ 0⤋
= 5.(x² + x - 6)
= 5.(x + 3).(x - 2)
2007-07-07 15:58:54 · answer #3 · answered by Como 7 · 0⤊ 0⤋
first pull out the common factor (5)
now you have 5*(x^2+x-6)
factor the inside (x+_)(x-_)
(x+3)(x-2) works
your answer is 5*(x+3)*(x-2)
2007-07-07 14:14:38 · answer #4 · answered by Richard F 1 · 0⤊ 0⤋