imagine an object of mass m oscillating, through a small angle, around an axis at point A, which is located a distance D away from the object's centre of mass, cm.
T is the period of oscillation.
how am i meant to show that this object's moment of inertia through the centre of mass, and parallel to the A axis, is given by
I = (MD/4π^2)(gT^2 - 4Dπ^2)
i havent got a clue how to do this, can it be clearly explained please?
thanks.
2007-11-23
01:39:37
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3 answers
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asked by
fpa06mr
5