A rectangular air mattress is 2.0 m long, 0.50 m wide, and 0.08 m thick. If it has a mass of 2.0 kg, what additional mass can it support in water?
I don't even know exactly what this question is trying to ask! Can anyone help me??????
2007-11-22 17:28:24 · 3 answers · asked by Eric S 2 in Science & Mathematics ➔ Physics
Get the total volume of the air mattress, which would be 0.08 cubic meters, or (0.08 x 10x10x10) cubic decimeters. That's 80 cubic decimeters, equivalent to 80 liters. A liter of water weighs one kilogram, so the air in the mattress should support 80 kg. Subtract the weight of the mattress itself, and it's supporting ability will be 78 kg, which is about right for the weight of one person.
2007-11-22 17:41:13 · answer #1 · answered by TitoBob 7 · 0⤊ 0⤋
enable x = the style of pavers 0.81x ? (10 * 20) Now remedy. 0.81x ? 200 x ? 246.ninety one because you want an entire volume, around as much as 247. you may want to have somewhat extra advantageous than 246 pavers so as to cover the entire area. x ? 247 of direction, they might want you to assert that x > 246, yet i'm undecided. The inequality you employ to remedy is particularly sparkling, nevertheless. answer 0.81x ? (10 * 20)
2016-12-16 16:31:46 · answer #2 · answered by evert 4 · 0⤊ 0⤋
question is based on Archimedes' principle: The mattress & additional weight will keep floating as long as the "weight of mattress and additional weight" are equal to the weight of water displaced. all you need to do is to subtract weight of mattress from displaced water's weight, this will give you "Additional weight".
2007-11-22 17:41:15 · answer #3 · answered by Dis part of my life is Happiness 1 · 0⤊ 0⤋