If given the trajectory equation as y=x*tan# - (g*x^2)/(2V^2*(cos#)^2)
where
y is the path of the trajectory
x is the horizontal distance
# is the angle it is launched at
g is gravity
V is launch velocity
how do you, using derivatives, find the equation to calculate the maximum height of an object being launch so that you can plug in velocity, gravity, and horizontal distance and equal the angle it should be launched at to reach maximum height
2007-11-27
09:23:06
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2 answers
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asked by
chibiams
1