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It takes 1200J of work to lift the car high enough to change a tire. How much work must be done by the person operating the jack if the jack is 25 percent effecient?

A windmill has an effeciency of 37.5 percent. If a gust of wind does 125J of work on the blades of the windmill, how much output work can the windmill do as a result of the gust?

Please WORK OUT THANKYUO

2007-11-27 10:23:21 · 1 answers · asked by abdo94 1 in Science & Mathematics Physics

1 answers

Efficiency = what you get out / what you put in.

For the jack problem you need to get 1200 J.

.25 = 1200 J / W

Solve for the work done, W

For the windmill problem, the wind did 125 J of work.

.375 = W / 125 J

Solve for the output work W

2007-11-27 10:31:05 · answer #1 · answered by jgoulden 7 · 0 0

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