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An atomic clock moves at 1400 km/h for 1.50 h as measured by an identical clock on the earth. HOw many nanoseconds slow will the moving clock be compared with the earth clock, at the end of the 1.50 h interval?

help please

2007-11-27 05:59:59 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

You need to use the Lorentz factor, L = 1 / sqrt(1 - (v/c)^2), where v is the velocity and c is the speed of light in a vacuum. Then t = t0 / L, where t0 is the passage of time observed by a stationary observer and t is the passage of time observed by an observer moving at velocity v. Convert 1.50 h, your t0, into seconds (by multiplying by 3600 s / h) and 1400 km/h into m/s (by multiplying by 1000 m / km and by 3600 s / h), and use c = 3 x 10^8 m/s or 299792458 for a more precise result. I found that the moving clock is .0035 seconds slow.

2007-11-29 02:42:25 · answer #1 · answered by DavidK93 7 · 0 0

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