Alright well I have a lab due tomorrow, and there's one question I need help with. We rolled a ball bearing off a table and we need to answer some stuff about it. Alright I'll give you the data first. The velocity is .813 m/s. The table is 1m high. The ball landed 35.66cm's away from the table. I need to calculate the time it took the ball to fall from the edge of the table to the ground. Normally I don't post homework problems on Yahoo Answers, but I'm really having trouble with it. Thanks for the help!
2007-11-27 07:16:29 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The time it takes is just the time to fall the 1 meter from teh table to the ground. I assume the ball was moving horizontally when it came off the table so you can find the time using:
y = 1/2gt^2 where g = 9.8 m/s^2
then t = sqrt(2y/g) =sqrt (1m/(2*9.8 m/s^2)) = 0.226 seconds
2007-11-27 07:23:31 · answer #1 · answered by nyphdinmd 7 · 0⤊ 0⤋