A spy satellite is in circular orbit around Earth. It makes one revolution in 6.03 hours. (Radius of the Earth=6.371 106 m)
(a) How high above Earth's surface is the satellite?
(b) What is the satellite's acceleration?
Without the correct asnwer to part A, i cannot get part b done.
The equation we were given is
r (height) = (G Me / w^2) ^1/3
i guess the question i have is, how to find w.
i took the gravitational constant of the earth, the mass of the earth, but the w (angular acceleration?) i cannot figure out.
thanks for the help.
2006-10-01
12:27:07
·
2 answers
·
asked by
robtrink
1