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No, the pull of gravity is not effected by speed. A similar question is: if you shoot a bullet on a level trajectory over a level ground and drop a same size and weight bullet at the same time which will land first. The answer is that they wil both land at the same time.

2006-10-01 13:33:37 · answer #1 · answered by daveduncan40 6 · 1 0

No way. The horizontal and the vertical motion of the ball are independent of each other. Both the balls hit the floor at the same time. The initial speed of the faster ball is used up in falling quickly. It is a common notion that the speed of the ball makes it fall a bit later than a ball just pushed off the edge of a table. A clear diagram illustrating this effect can be seen in the book 'Fundamentals of Physics' by Resnick & Halliday (Page#56). Hope you got the point.

2006-10-01 13:53:37 · answer #2 · answered by vijay s 1 · 0 0

In the absence of air, all balls would hit the ground at the same time, regardless of initial speed. The horizontal speed does not add to or subtract from the perpendicular action of gravitiy.

However, if you roll the ball fast enough in air, the leading surface will be spinning upward and may provide some lift to delay its fall, the same way that a curve-ball pitch works.

If you slide the ball off the table (not spinning), even in air they should all fall the same (unless you get up to speeds in the range of a bullet, in which case you will have the effect of terminal velocity, which may delay it's fall slightly).

2006-10-01 13:36:27 · answer #3 · answered by eric.s 3 · 0 0

in simple terms, gravity acts upon it the same no matter how fast it is, but since the object would be going a farther distance from a faster speed, the time it takes to hit the ground is extended. gravity doesnt try harder to pull down a fast object. it has the same force as a slow object, so a fast object takes longer to hit the floor because the path it follows is a longer, more gentle curve, then a slow ball ball would take.

2006-10-01 13:42:46 · answer #4 · answered by Spencer 1 · 0 0

No. the place it hits the floor will remember on the fee whilst it leaves the table, however the rigidity of gravity will deliver it to the floor in a similar quantity of time despite if it slowly rolls off the side and lands close to the table or if it on the instant flies off the table and lands far away.

2016-10-18 08:02:29 · answer #5 · answered by ? 4 · 0 0

Vijay S is right. Both balls will hit the floor at the same time. Both the balls, i.e slower and faster are cases of horizontal projectile motion, and hence time of flight is independent of velocity of projection. It depends only on height from which it is projected. As height is same in both cases, both bodies take same time to hit the ground.
To understand this easily: a slower ball has less velocity, so it will fall near to the table. So, its path of projection is less. But, in the case of the second ball, it has great velocity and so falls far from the table and hence has a lot of distance to cover. This ball has lots of distance to cover, but at the same time, as its velocity is also great it takes the same time as a slower ball to reach the ground.

2006-10-01 22:51:11 · answer #6 · answered by Alan 2 · 0 0

it depends on the how wide it could fly.
if there's not a wide limit, it will just drop on the floor by how tall it is released. In that way, the ball is only infected by the gravity( g=9.8 m/s). so time is connected to the height, not width. Unless when it's too near, the ball will hit the wall in advance

2006-10-01 13:33:28 · answer #7 · answered by Anonymous · 0 0

In reality, the spin rate of the ball will affect the speed at which the ball falls--but not by much since the ball is so smooth.

2006-10-01 13:27:24 · answer #8 · answered by bruinfan 7 · 0 0

yes speed does count if its a fast ball it'll be shorter

2006-10-01 13:25:56 · answer #9 · answered by nicegirl2 2 · 0 0

No.
The vertical and horizontal components of force are independent.

2006-10-02 02:44:07 · answer #10 · answered by Math_Guru 2 · 0 0

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