How would you solve the following difficult problem below?
For the force field F(x,y,z)=(ze^x cos y) i - (ze^x sin y) j + (e^x cos y) k, calculate the work done by F on an object moving along a curve from (0, 0, 0) to (2, π/2, 1)
these were the possible answers given....
-2
-2 - 4e^2
0
-2e
-3e^2
-4e^2
I’ve gotten this far with it….
Px= z e^x cosy so P = z e^x cosy +f(y,z)
Py =- z e^xsin y so P = z e^x cos y +h(xz)
Pz = e^x cos y so P= z e^x cos y + g(x,y)
so
P= z e^x cos y is the potential function and the integral is
1*e^2*0- 0*1*1=0
Now how would you go about solving this….?
2007-08-05
09:43:40
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2 answers
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asked by
Jake
1