convert this polar equation to rectangular form (steps also)---> r=2cos(theta)?

Answer 1

r = 2cos(theta)

x = r cos(theta) = 2r cos^2(theta) = r(cos(2 theta) + 1).
y = r sin(theta) = 2r sin(theta)cos(theta) = r sin(2 theta).

Answer 2

Convert the polar equation to rectangular type. r = 3cos? ________ endure in techniques the identities. x = rcos? y = rsin? x² + y² = r² _________ r = 3cos? r² = 3rcos? x² + y² = 3x x² - 3x + y² = 0 (x² - 3x + 9/4) + y² = 9/4 (x - 3/2)² + y² = 9/4 it rather is the equation of a circle with center (3/2,0) and radius 3/2.

Answer 3

Remember the identities.

x = rcosθ
y = rsinθ
x² + y² = r²
__________

r = 2cosθ
r² = 2rcosθ

x² + y² = 2x
x² - 2x + y² = 0
(x² - 2x + 1) + y² = 0 + 1
(x - 1)² + y² = 1