One Friday evening, Mary walked from her house to Sheila's house at a constant speed, arrived at Sheila's house at 8 pm, and then they both immediately walked the same route back to Mary's house. Next Friday, Sheila was ready earlier than usual and started to walk along the route towards Mary's house at some time before 8 pm. She met Mary coming towards her along the route, at which point, Mary turned around and walked back to her house with Sheila. On this occasion they reached Mary's house exactly 16 minutes earlier than on the previous Friday. If the two friends walked at the same constant speed on both Fridays, and Mary left her house at the same time both days, how many minutes before 8 do they met the second day?
2007-02-12
08:52:45
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6 answers
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asked by
pablo mablo
2
in
Jokes & Riddles