English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

One Friday evening, Mary walked from her house to Sheila's house at a constant speed, arrived at Sheila's house at 8 pm, and then they both immediately walked the same route back to Mary's house. Next Friday, Sheila was ready earlier than usual and started to walk along the route towards Mary's house at some time before 8 pm. She met Mary coming towards her along the route, at which point, Mary turned around and walked back to her house with Sheila. On this occasion they reached Mary's house exactly 16 minutes earlier than on the previous Friday. If the two friends walked at the same constant speed on both Fridays, and Mary left her house at the same time both days, how many minutes before 8 do they met the second day?

2007-02-12 08:52:45 · 6 answers · asked by pablo mablo 2 in Entertainment & Music Jokes & Riddles

6 answers

I think the answer is 8 minutes. Although there are a lot of 'unknowns', they seem to be largely irrelevant. If we look at it from a different perspective and take the second situation first, we know that they meet and then turn around to walk back to Mary's house. In the first situation we know that Mary walks all the way to Sheila's house and because of this, the overall journey back to Mary's house takes 16 minutes longer. This 16 minutes must consist of 8 minutes further to Sheila's house and 8 more minutes to get back to the same place.

So I think the answer is 8 minutes.

2007-02-12 11:29:29 · answer #1 · answered by brainyandy 6 · 1 0

The answer is 8 minutes.

Because as the assumptionis given that both friends walked at the same constant speed on both fridays and mary left her house the same time on both days, mary have to travel the same distance back after meeting Sheela.

So she might have taken the same time to come back. Since they reached mary's home 16 minutes earlier than the previous friday, she might have met sheela exactly at 7 hours and 52 mins that is 8 minutes before 8.

Assume she started @7 both days if she meets sheela at 7:52 then she might have taken the same 52 minutes to reach home sparing 16 minutes. Hence the solution.

2007-02-14 00:46:47 · answer #2 · answered by Koda 1 · 0 0

16 mins

2007-02-12 10:17:23 · answer #3 · answered by UhOH! 2 · 0 0

my brain hurts just reading that one, is it even possible to work out the answer

2007-02-12 08:58:59 · answer #4 · answered by tonywuzere 5 · 0 0

my mind is frozen ... i need to microwave it.

2007-02-15 17:21:11 · answer #5 · answered by 12-07-1941 3 · 0 0

i dunno 45 minutes

2007-02-12 09:11:16 · answer #6 · answered by Anonymous · 0 0

fedest.com, questions and answers