We are looking at a 20' tall tower with three parallel sides. (perpendicular to the ground) The angled front face is @ 81 degrees. The upper portion of our tower is 5' x 3’ with its base measuring 2' x 3'. The center of gravity is out side of this base and it will tip over. How do I determine the amount of force required to prevent this. (Currently, two steel feet, connected to the towers base, are meant to prevent its tipping. I believe that due to the weight of each of the eight panels [50lbs each] and the degree to which the front face is angled, that the feet will not be sufficient to prevent its tipping unless additional weight is added to each footing) Please Advise
2007-02-06
06:01:15
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1 answers
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asked by
ALH
1