Two blocks with masses m1 = 1.10 kg and m2 = 3.40 kg are connected by a massless string, as shown in the Figure. They are released from rest. The coefficent of kinetic friction between the upper block and the surface is 0.250.
Assume that the pulley has a negligible mass and is frictionless, and calculate the speed of the blocks after they have moved a distance 52.0 cm.
2007-02-06 04:00:47 · 3 answers · asked by bud 1 in Science & Mathematics ➔ Physics
You want to find the acceleration of the system. Assuming the heavier block is the one hanging from the pulley, you should be able to come up with two equations using F=ma.
(3.4kg)(9.8) - Tension = (3.4kg)(a)
&
Tension - (.250)(1.1kg)(9.8) = (1.1kg)(a)
By setting Tension equal to each other you can solve for a.
a=6.8m/s^2
Plug this acceleration into a kinematic equation to get final speed
Vf^2 = 0^2 + 2(6.8m/s^2)(.52m)
Velocity = 2.66 m/s
2007-02-06 04:46:26 · answer #1 · answered by gansta 2 · 1⤊ 0⤋
Have you tried to work these questions? It looks like you just pasted it in without reading it. Otherwise, why would you include "as shown in the Figure" without giving us the figure?
2007-02-06 05:29:37 · answer #2 · answered by sojsail 7 · 0⤊ 2⤋
please give the figure....
try using the formula.... F=uN; u- Coeff of friction,
N- normal component of weight
wieght=mg;
the whole system will be in equilirum.
Forces acting are mass of Bodies along the direction of motion and the Friction opposite to the direction of motion.
2007-02-06 04:54:27 · answer #3 · answered by MobiGuru 2 · 0⤊ 0⤋