A sled weighing 60.0N is pulled horizontally across snow so that the coefficient of kinetic friction between the sled and the snow is 0.100. A penguin weighing 70.0N rides on the sled. If the coefficient of static friction between the penguin and the sled is 0.700, find the maximum horizontal force that can be exerted on the sled before the penguin begins to slide off.
I'm not sure what the answer is.
I asserted that since the penguin is on the sled the normal force of the system is 130N, so I found the force of friction using the coefficient of kinetic friction to be 13N. Then I found the force of friction of the penguin sliding off, using the coefficient of static friction and a normal force of 70N of the penguin, to be 49N. I said that since it is moving at a constant speed there has to be a force of 13N on the sled already, so if I subtract 13N from 49N I would get 36N. So 36N is the force that is needed to slide the penguin off, right? or would it be 13N+49N=62N? Thanks so much!
2006-10-31
04:30:54
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2 answers
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asked by
akujinduck
1