2006-10-31 01:08:27 · 3 answers · asked by einstein 1 in Science & Mathematics ➔ Physics
Let 'g' be the acceleration due to gravity, 'G' be the Universal gravitational constant, 'M' be the mass of the earth and 'R' the radius of the earth.
Mass of earth = 6*10^24kg
Radius of earth = 6.4*10^6m
G = 6.7*[(1/10)^11] N m^ kg^2
g = G[M/(R)^2]
= {6.7*[(1/10)^11] N m^ kg^2}{6*10^24kg}/(6.4*10^6m)^2
= {6.7*6*10^13}/(6400000)^2
= (402*10^12/4096*10^10
= 40200/4096
= 9.8 m/s^2
This is how we get to know that acceleration due to gravity is 9.8m/s^2
2006-10-31 01:36:38 · answer #1 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
Modern work on gravitational theory began with the work of Galileo Galilei in the late 16th century and early 17th century. In his famous experiment dropping balls at the Tower of Pisa and later with careful measurements of balls rolling down inclines, Galileo showed that gravitation accelerates all objects at the same rate.
2006-10-31 09:24:05 · answer #2 · answered by trung l 1 · 1⤊ 1⤋
It was determined experimentally.
2006-10-31 09:27:09 · answer #3 · answered by bham0714 2 · 0⤊ 1⤋