So I have to find the concentration of lead in seawater. I prepared a 50 mL sample of seawater containing 0.1 M KCl, 50 mM HNO3 and 30 ppm HG2+. I took 15 ml of the above sample and spiked the sample with 1 ppm Pb2+ and Cd2+ to get a final concentration of 0.01 ppm Pb2+ and Cd2+. Then i spiked the sample again with the 1ppm Pb2+ and Cd2+ to make 0.025 ppm Pb2+ and Cd2+. I continued to spike the sample until I go 0.05, 0.075, and 0.1 ppm Pb2+ and Cd2+. For lead my results were:
0 ppm = -719 mV
0.05 ppm = -708 mV
0.075 ppm = -702 mV
0.1 ppm = -698 mv
The above is for the seawater sample. My standards are below:
0.05 ppm = -719 mV
0.1 ppm = -718 mV
0.5 ppm = -708 mV
Can someone please show me how to get this concentration?
2006-11-03
01:30:41
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1 answers
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asked by
Anonymous