The equation (x-1)^2+(y-2)^2+(z-3)^2=9 represents a sphere in 3D space. Find the equation in the form of Ax+By+Cz+D=0 of the plance that is tangent to the sphere at (2,4,5), a point at one end of the diameter of the sphere.
Can someone please explain to me in detail, i've not learn how to solve this in class.
Thanks.
Oh and also,
How do you find the equation of the sphere whith centre (2,1,3) and tangent to the plane 3x-4y+2z=12.
Im really confused that this point, but i managed to start the question and am stuck now.
2007-01-15
12:38:07
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5 answers
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asked by
Anonymous
in
Mathematics