If E=mc^2
then
mass= E/C^2, current speed of light is x meters/sec.
and E energy is in the order of joules
so mass= joules * sec^2 / meters ^2 , so does this imply that in order for mass to exist, time must exist
say time =0, then m = joules *0^2/ meters^2 =0
now consider a graph such as y=2x, obviouly the slope is 2 the rise over the run, impling that we can integrate to get the area under the curve
now going back
Let sec^2 = time for conviniance
and meter^2 = distance
mass = joules *time/ distance
now take the integral of both sides, by using time/ distance slope
integral(mass) = integral(joules*d(time)/d(distance))
mass is constant
joules are constant
so
mass= joules* integral ( dt/dd), dt/dd = instantaneous slope of time over distance
so time and distance are related ?
going back E=mC^2,
so 1/C^2 = integral ( dt/dd)
???
Im intrested in this subject, if you have any derivations or theories plz share :)
2007-04-13
21:15:26
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2 answers
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asked by
dragongml
3