I am currently doing limiting reagent and excess part of it, and i have trouble, with calculating here is the question
N2 + 3H2 ---> 2NH3
How many grams of NH3 can be produced from the reaction of 28g N2 and 25g of H2?
I did 25g divide 2g = 12.5mols then divide by 3= 4.17mols
28g divide by 28g = 1 mol then divde by 1= 1 mol
so 1 mol is limiting and the 4.17 is excess
i use 1 mol times 2NH3 divide by 1 N2 = 2 mols x 17g = 34g of NH3
then the second part asks How much of the excess reagent in problem 1 is left over?
im assuming thats the 4.17mols, and i cannot find how to figure it out, becuase my answers does not match the answer on back of book..so please someone help, thanks
2007-07-25
12:17:41
·
2 answers
·
asked by
playpwnsu
2