Can someone please help with this Chem?

Question

Aerobic respiration, or the process by which animals use energy by breaking down glucose in the presents of oxygen, is described by the equation:

C6H12O6+O2>>>CO2+H2O

Balance the equation.

Calculate how much carbon dioxide is exhaled if an animal inhales 32.0 gO2

What is the source of the glucose and oxygen?

Answer 1

C6H12O6+6O2>>>6CO2+6H20
32g of O2 is 1 mol of O2 right?(Periodic table)
thus from the equation 6O2 : 6CO2
1 mol of CO2 which is 16+16+12= 44g of Carbon Dioxide
glucose is from sugar or broken down carbohydrates which are from food and is stored in your body eg. liver
oxygen is from the air...

best of luck!!

Answer 2

Since each molecule of glucose can provide the carbon for 6 CO2 and the hydrogen for 6H2O, the complete conversion requires 18 O. Since 6 are supplied by the glucose, the other 12 must be from externally-supplied oxygen. Since gaseous oxygen is a dimer,
Glucose+ 6O2 -> 6 CO2 + 6 H2O

32 g of O2 is one mole of the dimer. For each mole of O2, one mole of CO2 is exhaled. Since a mole of CO2 is 44g, that's the answer.

Glucose is formed from food and transferred to cells, and oxygen is inhaled, and transferred to cells via the circulatory system.

Answer 3

well balanced I believe it is C6H12O6 + 6O2--> 6CO2 + 6H20

But thats about all I can help with