A hydrocarbon C14H12 contains 93.33% carbon and 6.67% hydrogen by mass.
The hydrocarbon has 2 structural isomers, W and X that contains 2 benzene rings respectively. W exhibits geometrical isomerism but X does not. In their reaction with HBr, W forms Y that is optically active, while X forms Z that is optically non-active. Determine the structure of W, X, Y, and Z.
Can you guys please teach me how to elaborate on ways to determine W, X, Y, and Z?
2007-04-23
02:07:39
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3 answers
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asked by
Adrianne G.
2