Here is the problem, " a calorimeter is filled with 150.0 g of water at 24.10 degrees C. A 50.0 g sample of metal at 100.0 degrees C is dropped into this calorimeter and causes the temperature to increase a total of 5.40 degrees C. What is the specific heat of the metal?
I understand how to calculate J/g C, (q=mc* change in temp [C]), how do I find specific heat (c) when I don't know the heat absorbed by the calorimeter?
2006-10-05
03:35:45
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3 answers
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asked by
historybuff2009
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